Python datetime模块的使用示例

脚本专栏 2024/12/23 佚名

3 2 1

1、获取当前年月日时分秒

# -*- encoding=utf-8 -*-
import datetime
now = datetime.datetime.now()
print("now:{}".format(now))
year = now.year
print("year:{}".format(year))
month = now.month
print("month:{}".format(month))
day = now.day
print("day:{}".format(day))
hour = now.hour
print("hour:{}".format(hour))
minute = now.minute
print("minute:{}".format(minute))
second = now.second
print("second:{}".format(second))

2、datetime转为string

# -*- encoding=utf-8 -*-
import datetime
now = datetime.datetime.now()
print('type:{}'.format(type(now)))
print('now datetime:{}'.format(now))
now_string = now.strftime('%Y-%m-%d %H:%M:%S')
print('type:{}'.format(type(now_string)))
print('now string:{}'.format(now_string))

3、string转为datetime

# -*- encoding=utf-8 -*-
import datetime
time_str = '2021-01-28 10:51:26'
time_date = datetime.datetime.strptime(time_str, '%Y-%m-%d %H:%M:%S')
print('type:{}'.format(type(time_date)))
print(time_date)

4、时间相加

# -*- encoding=utf-8 -*-
import datetime
time_str = '2021-01-28 10:00:00'
time_date = datetime.datetime.strptime(time_str, '%Y-%m-%d %H:%M:%S')
print('原始时间:\t\t\t\t{}'.format(time_date))
add_info = datetime.timedelta(days=1, hours=2, minutes=3, seconds=4)
add_end = time_date + add_info
print('加上1天2个小时3分钟4秒后:\t{}'.format(add_end))

5、时间相减

①两个时间差

# -*- encoding=utf-8 -*-
import datetime
time_str = '2021-01-28 10:00:00'
time_date = datetime.datetime.strptime(time_str, '%Y-%m-%d %H:%M:%S')
print('原始时间:\t{}'.format(time_date))
time_str = '2021-05-29 12:12:12'
time_date2 = datetime.datetime.strptime(time_str, '%Y-%m-%d %H:%M:%S')
print('原始时间2:\t{}'.format(time_date2))
time_date3 = time_date2 - time_date
print('时间差:{}'.format(time_date3))

②减去1天2个小时3分钟4秒（加负数）

# -*- encoding=utf-8 -*-
import datetime
time_str = '2021-01-28 10:00:00'
time_date = datetime.datetime.strptime(time_str, '%Y-%m-%d %H:%M:%S')
print('原始时间:\t\t\t\t{}'.format(time_date))
add_info = datetime.timedelta(days=-1, hours=-2, minutes=-3, seconds=-4)
add_end = time_date + add_info
print('减去1天2个小时3分钟4秒后:\t{}'.format(add_end))