解决python ThreadPoolExecutor 线程池中的异常捕获问题

脚本专栏 2024/11/8 佚名

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问题

最近写了涉及线程池及线程的 python 脚本，运行过程中发现一个有趣的现象，线程池中的工作线程出现问题，引发了异常，但是主线程没有捕获异常，还在发现 BUG 之前一度以为线程池代码正常返回。

先说重点

这里主要想介绍 python concurrent.futuresthread.ThreadPoolExecutor 线程池中的 worker 引发异常的时候，并不会直接向上抛起异常，而是需要主线程通过调用concurrent.futures.Future.exception(timeout=None) 方法主动获取 worker 的异常。

问题重现及解决

引子

问题主要由这样一段代码引起的：

def thread_executor():
 logger.info("I am slave. I am working. I am going to sleep 3s")
 sleep(3)
 logger.info("Exit thread executor")


def main():
 thread_obj = threading.Thread(target=thread_executor)
 while True:
  logger.info("Master starts thread worker")

  try:
   # 工作线程由于某种异常而结束并退出了，想重启工作线程的工作，但又不想重复创建线程
   thread_obj.start() # 这一行会报错，同一线程不能重复启动
  except Exception as e:
   logger.error("Master start thread error", exc_info=True)
   raise e

  logger.info("Master is going to sleep 5s")
  sleep(5)

上面这段代码的功能如注释中解释的，主要要实现类似生产者消费者的功能，工作线程一直去生产资源，主线程去消费工作线程生产的资源。但是工作线程由于异常推出了，想重新启动生产工作。显然，这个代码会报错。

运行结果:

thread: MainThread [INFO] Master starts thread worker
thread: Thread-1 [INFO] I am slave. I am working. I am going to sleep 3s
thread: MainThread [INFO] Master is going to sleep 5s
thread: Thread-1 [INFO] Exit thread executor because of some exception
thread: MainThread [INFO] Master starts thread worker
thread: MainThread [ERROR] Master start thread error
Traceback (most recent call last):
File "xxx.py", line 47, in main
 thread_obj.start()
File "E:\anaconda\lib\threading.py", line 843, in start
 raise RuntimeError("threads can only be started once")
RuntimeError: threads can only be started once
Traceback (most recent call last):
File "xxx.py", line 56, in <module>
 main()
File "xxx.py", line 50, in main
 raise e
File "xxx.py", line 47, in main
 thread_obj.start()
File "E:\anaconda\lib\threading.py", line 843, in start
 raise RuntimeError("threads can only be started once")
RuntimeError: threads can only be started once

切入正题

然而脚本还有其他业务代码要运行，所以需要把上面的资源生产和消费的代码放到一个线程里完成，所以引入线程池来执行这段代码：

def thread_executor():
 while True:
  logger.info("I am slave. I am working. I am going to sleep 3s")
  sleep(3)
  logger.info("Exit thread executor because of some exception")
  break


def main():
 thread_obj = threading.Thread(target=thread_executor)
 while True:
  logger.info("Master starts thread worker")

  # 工作线程由于某种异常而结束并退出了，想重启工作线程的工作，但又不想重复创建线程
  # 没有想到这里会有异常
  thread_obj.start() # 这一行会报错，同一线程不能重复启动

  logger.info("Master is going to sleep 5s")
  sleep(5)


def thread_pool_main():
 thread_obj = ThreadPoolExecutor(max_workers=1, thread_name_prefix="WorkExecutor")
 logger.info("Master ThreadPool Executor starts thread worker")
 thread_obj.submit(main)

 while True:
  logger.info("Master ThreadPool Executor is going to sleep 5s")
  sleep(5)

if __name__ == '__main__':
 thread_pool_main()

代码运行结果如下:

INFO [thread: MainThread] Master ThreadPool Executor starts thread worker
INFO [thread: WorkExecutor_0] Master starts thread worker
INFO [thread: MainThread] Master ThreadPool Executor is going to sleep 5s
INFO [thread: Thread-1] I am slave. I am working. I am going to sleep 3s
INFO [thread: WorkExecutor_0] Master is going to sleep 5s
INFO [thread: Thread-1] Exit thread executor because of some exception
INFO [thread: MainThread] Master ThreadPool Executor is going to sleep 5s
INFO [thread: WorkExecutor_0] Master starts thread worker
INFO [thread: MainThread] Master ThreadPool Executor is going to sleep 5s
INFO [thread: MainThread] Master ThreadPool Executor is going to sleep 5s
INFO [thread: MainThread] Master ThreadPool Executor is going to sleep 5s
INFO [thread: MainThread] Master ThreadPool Executor is going to sleep 5s
INFO [thread: MainThread] Master ThreadPool Executor is going to sleep 5s
INFO [thread: MainThread] Master ThreadPool Executor is going to sleep 5s
INFO [thread: MainThread] Master ThreadPool Executor is going to sleep 5s

... ...

显然，由上面的结果，在线程池 worker 执行到 INFO [thread: WorkExecutor_0] Master starts thread worker 的时候，是会有异常产生的，但是整个代码并没有抛弃任何异常。

解决方法

发现上面的 bug 后，想在线程池 worker 出错的时候，把异常记录到日志。查阅资料，要获取线程池的异常信息，需要调用 concurrent.futures.Future.exception(timeout=None) 方法，为了记录日志，这里加了线程池执行结束的回调函数。同时，日志中记录异常信息，用了 logging.exception() 方法。

def thread_executor():
 while True:
  logger.info("I am slave. I am working. I am going to sleep 3s")
  sleep(3)
  logger.info("Exit thread executor because of some exception")
  break


def main():
 thread_obj = threading.Thread(target=thread_executor)
 while True:
  logger.info("Master starts thread worker")

  # 工作线程由于某种异常而结束并退出了，想重启工作线程的工作，但又不想重复创建线程
  # 没有想到这里会有异常
  thread_obj.start() # 这一行会报错，同一线程不能重复启动

  logger.info("Master is going to sleep 5s")
  sleep(5)


def thread_pool_callback(worker):
 logger.info("called thread pool executor callback function")
 worker_exception = worker.exception()
 if worker_exception:
  logger.exception("Worker return exception: {}".format(worker_exception))


def thread_pool_main():
 thread_obj = ThreadPoolExecutor(max_workers=1, thread_name_prefix="WorkExecutor")
 logger.info("Master ThreadPool Executor starts thread worker")
 thread_pool_exc = thread_obj.submit(main)
 thread_pool_exc.add_done_callback(thread_pool_callback)
 # logger.info("thread pool exception: {}".format(thread_pool_exc.exception()))

 while True:
  logger.info("Master ThreadPool Executor is going to sleep 5s")
  sleep(5)


if __name__ == '__main__':
 thread_pool_main()

代码运行结果:

INFO [thread: MainThread] Master ThreadPool Executor starts thread worker
INFO [thread: WorkExecutor_0] Master starts thread worker
INFO [thread: MainThread] Master ThreadPool Executor is going to sleep 5s
INFO [thread: Thread-1] I am slave. I am working. I am going to sleep 3s
INFO [thread: WorkExecutor_0] Master is going to sleep 5s
INFO [thread: Thread-1] Exit thread executor because of some exception
INFO [thread: MainThread] Master ThreadPool Executor is going to sleep 5s
INFO [thread: WorkExecutor_0] Master starts thread worker
INFO [thread: WorkExecutor_0] called thread pool executor callback function
ERROR [thread: WorkExecutor_0] Worker return exception: threads can only be started once
Traceback (most recent call last):
File "E:\anaconda\lib\concurrent\futures\thread.py", line 57, in run
 result = self.fn(*self.args, **self.kwargs)
File "xxxx.py", line 46, in main
 thread_obj.start() # 这一行会报错，同一线程不能重复启动
File "E:\anaconda\lib\threading.py", line 843, in start
 raise RuntimeError("threads can only be started once")
RuntimeError: threads can only be started once
INFO [thread: MainThread] Master ThreadPool Executor is going to sleep 5s
INFO [thread: MainThread] Master ThreadPool Executor is going to sleep 5s
INFO [thread: MainThread] Master ThreadPool Executor is going to sleep 5s
... ...

最终的写法

其实，上面写法中，想重复利用一个线程去实现生产者线程的实现方法是有问题的，在此处，一般情况下，线程执行结束后，线程资源会被会被操作系统，所以线程不能被重复调用 start() 。

一种可行的实现方式就是，用线程池替代。当然，这样做得注意上面提到的线程池执行体的异常捕获问题。

def thread_executor():
 while True:
  logger.info("I am slave. I am working. I am going to sleep 3s")
  sleep(3)
  logger.info("Exit thread executor because of some exception")
  break

def executor_callback(worker):
 logger.info("called worker callback function")
 worker_exception = worker.exception()
 if worker_exception:
  logger.exception("Worker return exception: {}".format(worker_exception))
  # raise worker_exception


def main():
 slave_thread_pool = ThreadPoolExecutor(max_workers=1, thread_name_prefix="SlaveExecutor")
 restart_flag = False
 while True:
  logger.info("Master starts thread worker")

  if not restart_flag:
   restart_flag = not restart_flag
   logger.info("Restart Slave work")
  slave_thread_pool.submit(thread_executor).add_done_callback(executor_callback)

  logger.info("Master is going to sleep 5s")
  sleep(5)

总结

这个问题主要还是因为对 Python 的 concurrent.futuresthread.ThreadPoolExecutor 不够了解导致的，接触这个包是在书本上，但是书本没完全介绍包的全部 API 及用法，所以代码产生异常情况后，DEBUG 了许久在真正找到问题所在。查阅 python docs 后才对其完整用法有所认识，所以，以后学习新的 python 包的时候还是可以查一查官方文档的。

参考资料

英文版: docs of python concurrent.futures

中文版: python docs concurrent.futures — 启动并行任务

exception(timeout=None)

返回由调用引发的异常。如果调用还没完成那么这个方法将等待 timeout 秒。如果在 timeout 秒内没有执行完成，concurrent.futures.TimeoutError 将会被触发。timeout 可以是整数或浮点数。如果 timeout 没有指定或为 None，那么等待时间就没有限制。

如果 futrue 在完成前被取消则 CancelledError 将被触发。

如果调用正常完成那么返回 None。