a =[2,3,4,5]

#第一种方法
for i in map(lambda i:i+1,a)

#第二种方法
for index,i in enumerate(a):
  a[index] +=1

print(a)

#第三种，简单列表生成式
a = [i+1 for i in a]
print(a)
#加个三元运算符
a = [ i *2 if i>3 else i for i in a]

def fib(num):
  count = 0
  a,b = 0 ,1 #a=0, b= 1
  while count < num:
    tmp = a
    a = b
    b = a + tmp
    #print(a)
    count +=1
    yield a #返回a, 同时挂起当前这个函数， a返回给了通过__next__()调用当前函数的人
    #return a
  print("done...")

f = fib(10)
print(f.__next__())