d1 = {"name":"python","bank":"icbc","country":china}
# reverse是否倒序,x[1]代表value,x[0]为key
d1 = sorted(d1.items(),lambda x: x[1],reverse=True)

d1 = {"name":"python","bank":"icbc","country":china}
d1 = sorted(d1.items())

l = [3,2,4,5]
l = sorted(l)  # 升序
# l = sorted(l,reverse=True)  # 降序

l = [3,2,3,5,1]
l = set(l)   # 使用set集合去重
l = list(l)   #
l = sorted(l)   # 排序

# 以age升序排序
L = [
  {"name":"python","age":12},
  {"name":"ghj","age":10},
  {"name":"java","age":17}
]
L = sorted(L,key=lambda x: x["age"])

# 指定列表，假设存储的是curList中的ID列表
sortList = ["4","3","5","2","1"]
# 当前列表
curList = [{"id":"1","province":"河南"},{"id":"2","province":"河北"},{"id":"3","湖南"},{"id":"4","province":"湖北"},{"id":"5","province":"江西"}]
# 根据指定列表中的ID顺序，对当前列表进行排序
curList = sorted(curList,key = lambda item:sortList.index(item["id"]))
print(curList)
# [{"id":"4","province":"湖北"},{"id":"3","province":"湖南"},{"id":"5","province":"江西"},{"id":"2","province":"河北"},{"id":"1","province":"河南"}]